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5(5x+2)-5(4x+1)+3(6x-4)=3(6x+1)-2(6x-3)+120
We move all terms to the left:
5(5x+2)-5(4x+1)+3(6x-4)-(3(6x+1)-2(6x-3)+120)=0
We multiply parentheses
25x-20x+18x-(3(6x+1)-2(6x-3)+120)+10-5-12=0
We calculate terms in parentheses: -(3(6x+1)-2(6x-3)+120), so:We add all the numbers together, and all the variables
3(6x+1)-2(6x-3)+120
We multiply parentheses
18x-12x+3+6+120
We add all the numbers together, and all the variables
6x+129
Back to the equation:
-(6x+129)
23x-(6x+129)-7=0
We get rid of parentheses
23x-6x-129-7=0
We add all the numbers together, and all the variables
17x-136=0
We move all terms containing x to the left, all other terms to the right
17x=136
x=136/17
x=8
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