5(5y+2)-6y=27

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Solution for 5(5y+2)-6y=27 equation: 



5(5y+2)-6y=27

We move all terms to the left:

5(5y+2)-6y-(27)=0

We add all the numbers together, and all the variables

-6y+5(5y+2)-27=0

We multiply parentheses

-6y+25y+10-27=0

We add all the numbers together, and all the variables

19y-17=0

We move all terms containing y to the left, all other terms to the right

19y=17

y=17/19

y=17/19

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