5(5y+3)=3(3y-5)

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Solution for 5(5y+3)=3(3y-5) equation: 



5(5y+3)=3(3y-5)

We move all terms to the left:

5(5y+3)-(3(3y-5))=0

We multiply parentheses

25y-(3(3y-5))+15=0



We calculate terms in parentheses: -(3(3y-5)), so:

3(3y-5)

We multiply parentheses

9y-15

Back to the equation:

-(9y-15)



We get rid of parentheses

25y-9y+15+15=0

We add all the numbers together, and all the variables

16y+30=0

We move all terms containing y to the left, all other terms to the right

16y=-30

y=-30/16

y=-1+7/8

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