5(5y-2)+12+2(4y+4)=10

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Solution for 5(5y-2)+12+2(4y+4)=10 equation: 


Simplifying
5(5y + -2) + 12 + 2(4y + 4) = 10

Reorder the terms:
5(-2 + 5y) + 12 + 2(4y + 4) = 10
(-2 * 5 + 5y * 5) + 12 + 2(4y + 4) = 10
(-10 + 25y) + 12 + 2(4y + 4) = 10

Reorder the terms:
-10 + 25y + 12 + 2(4 + 4y) = 10
-10 + 25y + 12 + (4 * 2 + 4y * 2) = 10
-10 + 25y + 12 + (8 + 8y) = 10

Reorder the terms:
-10 + 12 + 8 + 25y + 8y = 10

Combine like terms: -10 + 12 = 2
2 + 8 + 25y + 8y = 10

Combine like terms: 2 + 8 = 10
10 + 25y + 8y = 10

Combine like terms: 25y + 8y = 33y
10 + 33y = 10

Add '-10' to each side of the equation.
10 + -10 + 33y = 10 + -10

Combine like terms: 10 + -10 = 0
0 + 33y = 10 + -10
33y = 10 + -10

Combine like terms: 10 + -10 = 0
33y = 0

Solving
33y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '33'.
y = 0

Simplifying
y = 0

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