5(5y-3)+11=4(y-1)-(2y+4)

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Solution for 5(5y-3)+11=4(y-1)-(2y+4) equation: 



5(5y-3)+11=4(y-1)-(2y+4)

We move all terms to the left:

5(5y-3)+11-(4(y-1)-(2y+4))=0

We multiply parentheses

25y-(4(y-1)-(2y+4))-15+11=0



We calculate terms in parentheses: -(4(y-1)-(2y+4)), so:

4(y-1)-(2y+4)

We multiply parentheses

4y-(2y+4)-4

We get rid of parentheses

4y-2y-4-4

We add all the numbers together, and all the variables

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

25y-(2y-8)-4=0

We get rid of parentheses

25y-2y+8-4=0

We add all the numbers together, and all the variables

23y+4=0

We move all terms containing y to the left, all other terms to the right

23y=-4

y=-4/23

y=-4/23

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