5(5z+2)=4(6z+3)

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Solution for 5(5z+2)=4(6z+3) equation: 



5(5z+2)=4(6z+3)

We move all terms to the left:

5(5z+2)-(4(6z+3))=0

We multiply parentheses

25z-(4(6z+3))+10=0



We calculate terms in parentheses: -(4(6z+3)), so:

4(6z+3)

We multiply parentheses

24z+12

Back to the equation:

-(24z+12)



We get rid of parentheses

25z-24z-12+10=0

We add all the numbers together, and all the variables

z-2=0

We move all terms containing z to the left, all other terms to the right

z=2

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