5(6+4/5b)=(9/10b)5

Solution for 5(6+4/5b)=(9/10b)5 equation:

5(6+4/5b)=(9/10b)5

We move all terms to the left:

5(6+4/5b)-((9/10b)5)=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10b)5)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

5(4/5b+6)-((+9/10b)5)=0

We multiply parentheses

20b-((+9/10b)5)+30=0

We multiply all the terms by the denominator


20b*10b)5)-((+30*10b)5)+9=0

Wy multiply elements

200b^2+300b=0

a = 200; b = 300; c = 0;
Δ = b2-4ac
Δ = 3002-4·200·0
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{90000}=300$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-300}{2*200}=\frac{-600}{400}
=-1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+300}{2*200}=\frac{0}{400}
=0
$