5(6+b)=b-2

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Solution for 5(6+b)=b-2 equation: 



5(6+b)=b-2

We move all terms to the left:

5(6+b)-(b-2)=0

We add all the numbers together, and all the variables

5(b+6)-(b-2)=0

We multiply parentheses

5b-(b-2)+30=0

We get rid of parentheses

5b-b+2+30=0

We add all the numbers together, and all the variables

4b+32=0

We move all terms containing b to the left, all other terms to the right

4b=-32

b=-32/4

b=-8

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