5(6-3x)+18=-9x-3(4-2x)

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Solution for 5(6-3x)+18=-9x-3(4-2x) equation: 



5(6-3x)+18=-9x-3(4-2x)

We move all terms to the left:

5(6-3x)+18-(-9x-3(4-2x))=0

We add all the numbers together, and all the variables

5(-3x+6)-(-9x-3(-2x+4))+18=0

We multiply parentheses

-15x-(-9x-3(-2x+4))+30+18=0



We calculate terms in parentheses: -(-9x-3(-2x+4)), so:

-9x-3(-2x+4)

We multiply parentheses

-9x+6x-12

We add all the numbers together, and all the variables

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

-15x-(-3x-12)+48=0

We get rid of parentheses

-15x+3x+12+48=0

We add all the numbers together, and all the variables

-12x+60=0

We move all terms containing x to the left, all other terms to the right

-12x=-60

x=-60/-12

x=+5

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