5(6-a)+2a=3(a-4)

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Solution for 5(6-a)+2a=3(a-4) equation: 



5(6-a)+2a=3(a-4)

We move all terms to the left:

5(6-a)+2a-(3(a-4))=0

We add all the numbers together, and all the variables

5(-1a+6)+2a-(3(a-4))=0

We add all the numbers together, and all the variables

2a+5(-1a+6)-(3(a-4))=0

We multiply parentheses

2a-5a-(3(a-4))+30=0



We calculate terms in parentheses: -(3(a-4)), so:

3(a-4)

We multiply parentheses

3a-12

Back to the equation:

-(3a-12)



We add all the numbers together, and all the variables

-3a-(3a-12)+30=0

We get rid of parentheses

-3a-3a+12+30=0

We add all the numbers together, and all the variables

-6a+42=0

We move all terms containing a to the left, all other terms to the right

-6a=-42

a=-42/-6

a=+7

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