5(6-a)+2a=3(a-4)

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Solution for 5(6-a)+2a=3(a-4) equation:



5(6-a)+2a=3(a-4)
We move all terms to the left:
5(6-a)+2a-(3(a-4))=0
We add all the numbers together, and all the variables
5(-1a+6)+2a-(3(a-4))=0
We add all the numbers together, and all the variables
2a+5(-1a+6)-(3(a-4))=0
We multiply parentheses
2a-5a-(3(a-4))+30=0
We calculate terms in parentheses: -(3(a-4)), so:
3(a-4)
We multiply parentheses
3a-12
Back to the equation:
-(3a-12)
We add all the numbers together, and all the variables
-3a-(3a-12)+30=0
We get rid of parentheses
-3a-3a+12+30=0
We add all the numbers together, and all the variables
-6a+42=0
We move all terms containing a to the left, all other terms to the right
-6a=-42
a=-42/-6
a=+7

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