5(6a-6)+40=3(10a-7)+31

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Solution for 5(6a-6)+40=3(10a-7)+31 equation:


Simplifying
5(6a + -6) + 40 = 3(10a + -7) + 31

Reorder the terms:
5(-6 + 6a) + 40 = 3(10a + -7) + 31
(-6 * 5 + 6a * 5) + 40 = 3(10a + -7) + 31
(-30 + 30a) + 40 = 3(10a + -7) + 31

Reorder the terms:
-30 + 40 + 30a = 3(10a + -7) + 31

Combine like terms: -30 + 40 = 10
10 + 30a = 3(10a + -7) + 31

Reorder the terms:
10 + 30a = 3(-7 + 10a) + 31
10 + 30a = (-7 * 3 + 10a * 3) + 31
10 + 30a = (-21 + 30a) + 31

Reorder the terms:
10 + 30a = -21 + 31 + 30a

Combine like terms: -21 + 31 = 10
10 + 30a = 10 + 30a

Add '-10' to each side of the equation.
10 + -10 + 30a = 10 + -10 + 30a

Combine like terms: 10 + -10 = 0
0 + 30a = 10 + -10 + 30a
30a = 10 + -10 + 30a

Combine like terms: 10 + -10 = 0
30a = 0 + 30a
30a = 30a

Add '-30a' to each side of the equation.
30a + -30a = 30a + -30a

Combine like terms: 30a + -30a = 0
0 = 30a + -30a

Combine like terms: 30a + -30a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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