5(6b-3)=5(2b+1)

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Solution for 5(6b-3)=5(2b+1) equation: 



5(6b-3)=5(2b+1)

We move all terms to the left:

5(6b-3)-(5(2b+1))=0

We multiply parentheses

30b-(5(2b+1))-15=0



We calculate terms in parentheses: -(5(2b+1)), so:

5(2b+1)

We multiply parentheses

10b+5

Back to the equation:

-(10b+5)



We get rid of parentheses

30b-10b-5-15=0

We add all the numbers together, and all the variables

20b-20=0

We move all terms containing b to the left, all other terms to the right

20b=20

b=20/20

b=1

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