5(6b-6)-3(b-2)=-51

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Solution for 5(6b-6)-3(b-2)=-51 equation: 



5(6b-6)-3(b-2)=-51

We move all terms to the left:

5(6b-6)-3(b-2)-(-51)=0

We add all the numbers together, and all the variables

5(6b-6)-3(b-2)+51=0

We multiply parentheses

30b-3b-30+6+51=0

We add all the numbers together, and all the variables

27b+27=0

We move all terms containing b to the left, all other terms to the right

27b=-27

b=-27/27

b=-1

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