5(6k+3)=1355(6k+3)=135

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Solution for 5(6k+3)=1355(6k+3)=135 equation: 



5(6k+3)=1355(6k+3)=135

We move all terms to the left:

5(6k+3)-(1355(6k+3))=0

We multiply parentheses

30k-(1355(6k+3))+15=0



We calculate terms in parentheses: -(1355(6k+3)), so:

1355(6k+3)

We multiply parentheses

8130k+4065

Back to the equation:

-(8130k+4065)



We get rid of parentheses

30k-8130k-4065+15=0

We add all the numbers together, and all the variables

-8100k-4050=0

We move all terms containing k to the left, all other terms to the right

-8100k=4050

k=4050/-8100

k=-1/2

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