5(6x+12)=3(10x+20)

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Solution for 5(6x+12)=3(10x+20) equation: 



5(6x+12)=3(10x+20)

We move all terms to the left:

5(6x+12)-(3(10x+20))=0

We multiply parentheses

30x-(3(10x+20))+60=0



We calculate terms in parentheses: -(3(10x+20)), so:

3(10x+20)

We multiply parentheses

30x+60

Back to the equation:

-(30x+60)



We get rid of parentheses

30x-30x-60+60=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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