5(6x+3)+2(x-1)=109

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Solution for 5(6x+3)+2(x-1)=109 equation: 



5(6x+3)+2(x-1)=109

We move all terms to the left:

5(6x+3)+2(x-1)-(109)=0

We multiply parentheses

30x+2x+15-2-109=0

We add all the numbers together, and all the variables

32x-96=0

We move all terms containing x to the left, all other terms to the right

32x=96

x=96/32

x=3

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