5(6x+4)+1=39-4(7-x)

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Solution for 5(6x+4)+1=39-4(7-x) equation: 



5(6x+4)+1=39-4(7-x)

We move all terms to the left:

5(6x+4)+1-(39-4(7-x))=0

We add all the numbers together, and all the variables

5(6x+4)-(39-4(-1x+7))+1=0

We multiply parentheses

30x-(39-4(-1x+7))+20+1=0



We calculate terms in parentheses: -(39-4(-1x+7)), so:

39-4(-1x+7)

determiningTheFunctionDomain
-4(-1x+7)+39

We multiply parentheses

4x-28+39

We add all the numbers together, and all the variables

4x+11

Back to the equation:

-(4x+11)



We add all the numbers together, and all the variables

30x-(4x+11)+21=0

We get rid of parentheses

30x-4x-11+21=0

We add all the numbers together, and all the variables

26x+10=0

We move all terms containing x to the left, all other terms to the right

26x=-10

x=-10/26

x=-5/13

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