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5(6x^2+5x)-7(6x+5)=0
We multiply parentheses
30x^2+25x-42x-35=0
We add all the numbers together, and all the variables
30x^2-17x-35=0
a = 30; b = -17; c = -35;
Δ = b2-4ac
Δ = -172-4·30·(-35)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-67}{2*30}=\frac{-50}{60} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+67}{2*30}=\frac{84}{60} =1+2/5 $
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