5(6y-3)+(6-5y)=48

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Solution for 5(6y-3)+(6-5y)=48 equation: 



5(6y-3)+(6-5y)=48

We move all terms to the left:

5(6y-3)+(6-5y)-(48)=0

We add all the numbers together, and all the variables

5(6y-3)+(-5y+6)-48=0

We multiply parentheses

30y+(-5y+6)-15-48=0

We get rid of parentheses

30y-5y+6-15-48=0

We add all the numbers together, and all the variables

25y-57=0

We move all terms containing y to the left, all other terms to the right

25y=57

y=57/25

y=2+7/25

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