5(6z+1)-7=148

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Solution for 5(6z+1)-7=148 equation:



5(6z+1)-7=148
We move all terms to the left:
5(6z+1)-7-(148)=0
We add all the numbers together, and all the variables
5(6z+1)-155=0
We multiply parentheses
30z+5-155=0
We add all the numbers together, and all the variables
30z-150=0
We move all terms containing z to the left, all other terms to the right
30z=150
z=150/30
z=5

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