5(6z+1)-7=148

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Solution for 5(6z+1)-7=148 equation: 



5(6z+1)-7=148

We move all terms to the left:

5(6z+1)-7-(148)=0

We add all the numbers together, and all the variables

5(6z+1)-155=0

We multiply parentheses

30z+5-155=0

We add all the numbers together, and all the variables

30z-150=0

We move all terms containing z to the left, all other terms to the right

30z=150

z=150/30

z=5

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