5(6z-1)-2(z+4)=16(z+1)

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Solution for 5(6z-1)-2(z+4)=16(z+1) equation: 



5(6z-1)-2(z+4)=16(z+1)

We move all terms to the left:

5(6z-1)-2(z+4)-(16(z+1))=0

We multiply parentheses

30z-2z-(16(z+1))-5-8=0



We calculate terms in parentheses: -(16(z+1)), so:

16(z+1)

We multiply parentheses

16z+16

Back to the equation:

-(16z+16)



We add all the numbers together, and all the variables

28z-(16z+16)-13=0

We get rid of parentheses

28z-16z-16-13=0

We add all the numbers together, and all the variables

12z-29=0

We move all terms containing z to the left, all other terms to the right

12z=29

z=29/12

z=2+5/12

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