5(6z-1)-4(z+4)=22(z+1)

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Solution for 5(6z-1)-4(z+4)=22(z+1) equation:


Simplifying
5(6z + -1) + -4(z + 4) = 22(z + 1)

Reorder the terms:
5(-1 + 6z) + -4(z + 4) = 22(z + 1)
(-1 * 5 + 6z * 5) + -4(z + 4) = 22(z + 1)
(-5 + 30z) + -4(z + 4) = 22(z + 1)

Reorder the terms:
-5 + 30z + -4(4 + z) = 22(z + 1)
-5 + 30z + (4 * -4 + z * -4) = 22(z + 1)
-5 + 30z + (-16 + -4z) = 22(z + 1)

Reorder the terms:
-5 + -16 + 30z + -4z = 22(z + 1)

Combine like terms: -5 + -16 = -21
-21 + 30z + -4z = 22(z + 1)

Combine like terms: 30z + -4z = 26z
-21 + 26z = 22(z + 1)

Reorder the terms:
-21 + 26z = 22(1 + z)
-21 + 26z = (1 * 22 + z * 22)
-21 + 26z = (22 + 22z)

Solving
-21 + 26z = 22 + 22z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-22z' to each side of the equation.
-21 + 26z + -22z = 22 + 22z + -22z

Combine like terms: 26z + -22z = 4z
-21 + 4z = 22 + 22z + -22z

Combine like terms: 22z + -22z = 0
-21 + 4z = 22 + 0
-21 + 4z = 22

Add '21' to each side of the equation.
-21 + 21 + 4z = 22 + 21

Combine like terms: -21 + 21 = 0
0 + 4z = 22 + 21
4z = 22 + 21

Combine like terms: 22 + 21 = 43
4z = 43

Divide each side by '4'.
z = 10.75

Simplifying
z = 10.75

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