5(6z-1)-4(z+5)=22(2+1)

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Solution for 5(6z-1)-4(z+5)=22(2+1) equation:


Simplifying
5(6z + -1) + -4(z + 5) = 22(2 + 1)

Reorder the terms:
5(-1 + 6z) + -4(z + 5) = 22(2 + 1)
(-1 * 5 + 6z * 5) + -4(z + 5) = 22(2 + 1)
(-5 + 30z) + -4(z + 5) = 22(2 + 1)

Reorder the terms:
-5 + 30z + -4(5 + z) = 22(2 + 1)
-5 + 30z + (5 * -4 + z * -4) = 22(2 + 1)
-5 + 30z + (-20 + -4z) = 22(2 + 1)

Reorder the terms:
-5 + -20 + 30z + -4z = 22(2 + 1)

Combine like terms: -5 + -20 = -25
-25 + 30z + -4z = 22(2 + 1)

Combine like terms: 30z + -4z = 26z
-25 + 26z = 22(2 + 1)

Combine like terms: 2 + 1 = 3
-25 + 26z = 22(3)

Multiply 22 * 3
-25 + 26z = 66

Solving
-25 + 26z = 66

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 26z = 66 + 25

Combine like terms: -25 + 25 = 0
0 + 26z = 66 + 25
26z = 66 + 25

Combine like terms: 66 + 25 = 91
26z = 91

Divide each side by '26'.
z = 3.5

Simplifying
z = 3.5

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