5(6z-1)-5(z+9)=21(z+1)

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Solution for 5(6z-1)-5(z+9)=21(z+1) equation: 



5(6z-1)-5(z+9)=21(z+1)

We move all terms to the left:

5(6z-1)-5(z+9)-(21(z+1))=0

We multiply parentheses

30z-5z-(21(z+1))-5-45=0



We calculate terms in parentheses: -(21(z+1)), so:

21(z+1)

We multiply parentheses

21z+21

Back to the equation:

-(21z+21)



We add all the numbers together, and all the variables

25z-(21z+21)-50=0

We get rid of parentheses

25z-21z-21-50=0

We add all the numbers together, and all the variables

4z-71=0

We move all terms containing z to the left, all other terms to the right

4z=71

z=71/4

z=17+3/4

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