5(7+2r)+3(r+1)=-4r-2r

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Solution for 5(7+2r)+3(r+1)=-4r-2r equation: 



5(7+2r)+3(r+1)=-4r-2r

We move all terms to the left:

5(7+2r)+3(r+1)-(-4r-2r)=0

We add all the numbers together, and all the variables

5(2r+7)+3(r+1)-(-6r)=0

We multiply parentheses

10r+3r-(-6r)+35+3=0

We get rid of parentheses

10r+3r+6r+35+3=0

We add all the numbers together, and all the variables

19r+38=0

We move all terms containing r to the left, all other terms to the right

19r=-38

r=-38/19

r=-2

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