5(7+2x)=3(x-4)-2

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Solution for 5(7+2x)=3(x-4)-2 equation: 



5(7+2x)=3(x-4)-2

We move all terms to the left:

5(7+2x)-(3(x-4)-2)=0

We add all the numbers together, and all the variables

5(2x+7)-(3(x-4)-2)=0

We multiply parentheses

10x-(3(x-4)-2)+35=0



We calculate terms in parentheses: -(3(x-4)-2), so:

3(x-4)-2

We multiply parentheses

3x-12-2

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We get rid of parentheses

10x-3x+14+35=0

We add all the numbers together, and all the variables

7x+49=0

We move all terms containing x to the left, all other terms to the right

7x=-49

x=-49/7

x=-7

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