5(7+4m)+3=7m-40

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Solution for 5(7+4m)+3=7m-40 equation: 



5(7+4m)+3=7m-40

We move all terms to the left:

5(7+4m)+3-(7m-40)=0

We add all the numbers together, and all the variables

5(4m+7)-(7m-40)+3=0

We multiply parentheses

20m-(7m-40)+35+3=0

We get rid of parentheses

20m-7m+40+35+3=0

We add all the numbers together, and all the variables

13m+78=0

We move all terms containing m to the left, all other terms to the right

13m=-78

m=-78/13

m=-6

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