5(7-a)-3(a+4)=4(a-3)+7

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Solution for 5(7-a)-3(a+4)=4(a-3)+7 equation: 



5(7-a)-3(a+4)=4(a-3)+7

We move all terms to the left:

5(7-a)-3(a+4)-(4(a-3)+7)=0

We add all the numbers together, and all the variables

5(-1a+7)-3(a+4)-(4(a-3)+7)=0

We multiply parentheses

-5a-3a-(4(a-3)+7)+35-12=0



We calculate terms in parentheses: -(4(a-3)+7), so:

4(a-3)+7

We multiply parentheses

4a-12+7

We add all the numbers together, and all the variables

4a-5

Back to the equation:

-(4a-5)



We add all the numbers together, and all the variables

-8a-(4a-5)+23=0

We get rid of parentheses

-8a-4a+5+23=0

We add all the numbers together, and all the variables

-12a+28=0

We move all terms containing a to the left, all other terms to the right

-12a=-28

a=-28/-12

a=2+1/3

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