5(7-d)-1=3(d-5)-15

Solution for 5(7-d)-1=3(d-5)-15 equation:

5(7-d)-1=3(d-5)-15

We move all terms to the left:

5(7-d)-1-(3(d-5)-15)=0

We add all the numbers together, and all the variables

5(-1d+7)-(3(d-5)-15)-1=0

We multiply parentheses

-5d-(3(d-5)-15)+35-1=0


We calculate terms in parentheses: -(3(d-5)-15), so:

3(d-5)-15

We multiply parentheses

3d-15-15

We add all the numbers together, and all the variables

3d-30

Back to the equation:

-(3d-30)


We add all the numbers together, and all the variables

-5d-(3d-30)+34=0

We get rid of parentheses

-5d-3d+30+34=0

We add all the numbers together, and all the variables

-8d+64=0

We move all terms containing d to the left, all other terms to the right

-8d=-64

d=-64/-8

d=+8