5(7bx+y)=34bx-4y

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Solution for 5(7bx+y)=34bx-4y equation:


Simplifying
5(7bx + y) = 34bx + -4y
(7bx * 5 + y * 5) = 34bx + -4y
(35bx + 5y) = 34bx + -4y

Solving
35bx + 5y = 34bx + -4y

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-34bx' to each side of the equation.
35bx + -34bx + 5y = 34bx + -34bx + -4y

Combine like terms: 35bx + -34bx = 1bx
1bx + 5y = 34bx + -34bx + -4y

Combine like terms: 34bx + -34bx = 0
1bx + 5y = 0 + -4y
1bx + 5y = -4y

Add '-5y' to each side of the equation.
1bx + 5y + -5y = -4y + -5y

Combine like terms: 5y + -5y = 0
1bx + 0 = -4y + -5y
1bx = -4y + -5y

Combine like terms: -4y + -5y = -9y
1bx = -9y

Divide each side by '1x'.
b = -9x-1y

Simplifying
b = -9x-1y

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