5(7f+5)=2(5f-1)

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Solution for 5(7f+5)=2(5f-1) equation:



5(7f+5)=2(5f-1)
We move all terms to the left:
5(7f+5)-(2(5f-1))=0
We multiply parentheses
35f-(2(5f-1))+25=0
We calculate terms in parentheses: -(2(5f-1)), so:
2(5f-1)
We multiply parentheses
10f-2
Back to the equation:
-(10f-2)
We get rid of parentheses
35f-10f+2+25=0
We add all the numbers together, and all the variables
25f+27=0
We move all terms containing f to the left, all other terms to the right
25f=-27
f=-27/25
f=-1+2/25

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