5(8ax+y)=39ax-2y

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Solution for 5(8ax+y)=39ax-2y equation:


Simplifying
5(8ax + y) = 39ax + -2y
(8ax * 5 + y * 5) = 39ax + -2y
(40ax + 5y) = 39ax + -2y

Solving
40ax + 5y = 39ax + -2y

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-39ax' to each side of the equation.
40ax + -39ax + 5y = 39ax + -39ax + -2y

Combine like terms: 40ax + -39ax = 1ax
1ax + 5y = 39ax + -39ax + -2y

Combine like terms: 39ax + -39ax = 0
1ax + 5y = 0 + -2y
1ax + 5y = -2y

Add '-5y' to each side of the equation.
1ax + 5y + -5y = -2y + -5y

Combine like terms: 5y + -5y = 0
1ax + 0 = -2y + -5y
1ax = -2y + -5y

Combine like terms: -2y + -5y = -7y
1ax = -7y

Divide each side by '1x'.
a = -7x-1y

Simplifying
a = -7x-1y

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