5(8b+2)=7(b-8)

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Solution for 5(8b+2)=7(b-8) equation: 



5(8b+2)=7(b-8)

We move all terms to the left:

5(8b+2)-(7(b-8))=0

We multiply parentheses

40b-(7(b-8))+10=0



We calculate terms in parentheses: -(7(b-8)), so:

7(b-8)

We multiply parentheses

7b-56

Back to the equation:

-(7b-56)



We get rid of parentheses

40b-7b+56+10=0

We add all the numbers together, and all the variables

33b+66=0

We move all terms containing b to the left, all other terms to the right

33b=-66

b=-66/33

b=-2

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