5(8b+2)=7(b-8)

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Solution for 5(8b+2)=7(b-8) equation:



5(8b+2)=7(b-8)
We move all terms to the left:
5(8b+2)-(7(b-8))=0
We multiply parentheses
40b-(7(b-8))+10=0
We calculate terms in parentheses: -(7(b-8)), so:
7(b-8)
We multiply parentheses
7b-56
Back to the equation:
-(7b-56)
We get rid of parentheses
40b-7b+56+10=0
We add all the numbers together, and all the variables
33b+66=0
We move all terms containing b to the left, all other terms to the right
33b=-66
b=-66/33
b=-2

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