5(8x+1)x1/2+8x3/2

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Solution for 5(8x+1)x1/2+8x3/2 equation:


x in (-oo:+oo)

(5*x^1*(8*x+1))/2+(8*x^3)/2 = 0

(5*x*(8*x+1))/2+(8*x^3)/2 = 0

(5*x*(8*x+1))/2+4*x^3 = 0

(5*x*(8*x+1))/2+(2*4*x^3)/2 = 0

5*x*(8*x+1)+2*4*x^3 = 0

8*x^3+40*x^2+5*x = 0

8*x^3+40*x^2+5*x = 0

x*(8*x^2+40*x+5) = 0

8*x^2+40*x+5 = 0

DELTA = 40^2-(4*5*8)

DELTA = 1440

DELTA > 0

x = (1440^(1/2)-40)/(2*8) or x = (-1440^(1/2)-40)/(2*8)

x = (12*10^(1/2)-40)/16 or x = (-12*10^(1/2)-40)/16

x*(x-((-12*10^(1/2)-40)/16))*(x-((12*10^(1/2)-40)/16)) = 0

(x*(x-((-12*10^(1/2)-40)/16))*(x-((12*10^(1/2)-40)/16)))/2 = 0

(x*(x-((-12*10^(1/2)-40)/16))*(x-((12*10^(1/2)-40)/16)))/2 = 0 // * 2

x*(x-((-12*10^(1/2)-40)/16))*(x-((12*10^(1/2)-40)/16)) = 0

( x-((-12*10^(1/2)-40)/16) )

x-((-12*10^(1/2)-40)/16) = 0 // + (-12*10^(1/2)-40)/16

x = (-12*10^(1/2)-40)/16

( x-((12*10^(1/2)-40)/16) )

x-((12*10^(1/2)-40)/16) = 0 // + (12*10^(1/2)-40)/16

x = (12*10^(1/2)-40)/16

( x )

x = 0

x in { (-12*10^(1/2)-40)/16, (12*10^(1/2)-40)/16, 0 }

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