5(8x-1)-7(4x+1)+8(7-4x)=9

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Solution for 5(8x-1)-7(4x+1)+8(7-4x)=9 equation:


5(8x-1)-7(4x+1)+8(7-4x)=9

We simplify the equation to the form, which is simple to understand
5(8x-1)-7(4x+1)+8(7-4x)=9

Reorder the terms in parentheses
+(+40x-5)-7*(4x+1)+8*(7-4x)=9

Remove unnecessary parentheses
+40x-5-7+*(+4x+1+)+8+*(+7-4x+)=+9

Reorder the terms in parentheses
+40x-5+(-28x-7)+8*(7-4x)=9

Remove unnecessary parentheses
+40x-5-28x-7+8+*(+7-4x+)=+9

Reorder the terms in parentheses
+40x-5-28x-7+(+56-32x)=9

Remove unnecessary parentheses
+40x-5-28x-7+56-32x=+9

We move all terms containing x to the left and all other terms to the right.
+40x-28x-32x=+9+5+7-56

We simplify left and right side of the equation.
-20x=-35

We divide both sides of the equation by -20 to get x.
x=1.75

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