5(8x-2)=6(1+6x)+2x

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Solution for 5(8x-2)=6(1+6x)+2x equation: 



5(8x-2)=6(1+6x)+2x

We move all terms to the left:

5(8x-2)-(6(1+6x)+2x)=0

We add all the numbers together, and all the variables

5(8x-2)-(6(6x+1)+2x)=0

We multiply parentheses

40x-(6(6x+1)+2x)-10=0



We calculate terms in parentheses: -(6(6x+1)+2x), so:

6(6x+1)+2x

We add all the numbers together, and all the variables

2x+6(6x+1)

We multiply parentheses

2x+36x+6

We add all the numbers together, and all the variables

38x+6

Back to the equation:

-(38x+6)



We get rid of parentheses

40x-38x-6-10=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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