5(8x-4)+2(5-4x)=20+3(2-6x)

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Solution for 5(8x-4)+2(5-4x)=20+3(2-6x) equation:



5(8x-4)+2(5-4x)=20+3(2-6x)
We move all terms to the left:
5(8x-4)+2(5-4x)-(20+3(2-6x))=0
We add all the numbers together, and all the variables
5(8x-4)+2(-4x+5)-(20+3(-6x+2))=0
We multiply parentheses
40x-8x-(20+3(-6x+2))-20+10=0
We calculate terms in parentheses: -(20+3(-6x+2)), so:
20+3(-6x+2)
determiningTheFunctionDomain 3(-6x+2)+20
We multiply parentheses
-18x+6+20
We add all the numbers together, and all the variables
-18x+26
Back to the equation:
-(-18x+26)
We add all the numbers together, and all the variables
32x-(-18x+26)-10=0
We get rid of parentheses
32x+18x-26-10=0
We add all the numbers together, and all the variables
50x-36=0
We move all terms containing x to the left, all other terms to the right
50x=36
x=36/50
x=18/25

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