5(8x-4)+2(5-4x)=20+3(2-6x)

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Solution for 5(8x-4)+2(5-4x)=20+3(2-6x) equation: 



5(8x-4)+2(5-4x)=20+3(2-6x)

We move all terms to the left:

5(8x-4)+2(5-4x)-(20+3(2-6x))=0

We add all the numbers together, and all the variables

5(8x-4)+2(-4x+5)-(20+3(-6x+2))=0

We multiply parentheses

40x-8x-(20+3(-6x+2))-20+10=0



We calculate terms in parentheses: -(20+3(-6x+2)), so:

20+3(-6x+2)

determiningTheFunctionDomain
3(-6x+2)+20

We multiply parentheses

-18x+6+20

We add all the numbers together, and all the variables

-18x+26

Back to the equation:

-(-18x+26)



We add all the numbers together, and all the variables

32x-(-18x+26)-10=0

We get rid of parentheses

32x+18x-26-10=0

We add all the numbers together, and all the variables

50x-36=0

We move all terms containing x to the left, all other terms to the right

50x=36

x=36/50

x=18/25

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