5(8y-2)=7-4(10y+8)

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Solution for 5(8y-2)=7-4(10y+8) equation: 



5(8y-2)=7-4(10y+8)

We move all terms to the left:

5(8y-2)-(7-4(10y+8))=0

We multiply parentheses

40y-(7-4(10y+8))-10=0



We calculate terms in parentheses: -(7-4(10y+8)), so:

7-4(10y+8)

determiningTheFunctionDomain
-4(10y+8)+7

We multiply parentheses

-40y-32+7

We add all the numbers together, and all the variables

-40y-25

Back to the equation:

-(-40y-25)



We get rid of parentheses

40y+40y+25-10=0

We add all the numbers together, and all the variables

80y+15=0

We move all terms containing y to the left, all other terms to the right

80y=-15

y=-15/80

y=-3/16

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