5(9-x)+8=16+2(2x-4)

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Solution for 5(9-x)+8=16+2(2x-4) equation: 



5(9-x)+8=16+2(2x-4)

We move all terms to the left:

5(9-x)+8-(16+2(2x-4))=0

We add all the numbers together, and all the variables

5(-1x+9)-(16+2(2x-4))+8=0

We multiply parentheses

-5x-(16+2(2x-4))+45+8=0



We calculate terms in parentheses: -(16+2(2x-4)), so:

16+2(2x-4)

determiningTheFunctionDomain
2(2x-4)+16

We multiply parentheses

4x-8+16

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

-5x-(4x+8)+53=0

We get rid of parentheses

-5x-4x-8+53=0

We add all the numbers together, and all the variables

-9x+45=0

We move all terms containing x to the left, all other terms to the right

-9x=-45

x=-45/-9

x=+5

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