5(9m-7)-6(3m-4)+60=3(7-2m)

Solution for 5(9m-7)-6(3m-4)+60=3(7-2m) equation:

5(9m-7)-6(3m-4)+60=3(7-2m)

We move all terms to the left:

5(9m-7)-6(3m-4)+60-(3(7-2m))=0

We add all the numbers together, and all the variables

5(9m-7)-6(3m-4)-(3(-2m+7))+60=0

We multiply parentheses

45m-18m-(3(-2m+7))-35+24+60=0


We calculate terms in parentheses: -(3(-2m+7)), so:

3(-2m+7)

We multiply parentheses

-6m+21

Back to the equation:

-(-6m+21)


We add all the numbers together, and all the variables

27m-(-6m+21)+49=0

We get rid of parentheses

27m+6m-21+49=0

We add all the numbers together, and all the variables

33m+28=0

We move all terms containing m to the left, all other terms to the right

33m=-28

m=-28/33

m=-28/33