5(B+1)=7(2-b)

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Solution for 5(B+1)=7(2-b) equation: 



5(+1)=7(2-B)

We move all terms to the left:

5(+1)-(7(2-B))=0

We add all the numbers together, and all the variables

-(7(-1B+2))+51=0



We calculate terms in parentheses: -(7(-1B+2)), so:

7(-1B+2)

We multiply parentheses

-7B+14

Back to the equation:

-(-7B+14)



We get rid of parentheses

7B-14+51=0

We add all the numbers together, and all the variables

7B+37=0

We move all terms containing B to the left, all other terms to the right

7B=-37

B=-37/7

B=-5+2/7

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