5(C+4)+2C=3(c+10)-2

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Solution for 5(C+4)+2C=3(c+10)-2 equation: 


Simplifying
5(C + 4) + 2C = 3(c + 10) + -2

Reorder the terms:
5(4 + C) + 2C = 3(c + 10) + -2
(4 * 5 + C * 5) + 2C = 3(c + 10) + -2
(20 + 5C) + 2C = 3(c + 10) + -2

Combine like terms: 5C + 2C = 7C
20 + 7C = 3(c + 10) + -2

Reorder the terms:
20 + 7C = 3(10 + c) + -2
20 + 7C = (10 * 3 + c * 3) + -2
20 + 7C = (30 + 3c) + -2

Reorder the terms:
20 + 7C = 30 + -2 + 3c

Combine like terms: 30 + -2 = 28
20 + 7C = 28 + 3c

Solving
20 + 7C = 28 + 3c

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 7C = 28 + -20 + 3c

Combine like terms: 20 + -20 = 0
0 + 7C = 28 + -20 + 3c
7C = 28 + -20 + 3c

Combine like terms: 28 + -20 = 8
7C = 8 + 3c

Divide each side by '7'.
C = 1.142857143 + 0.4285714286c

Simplifying
C = 1.142857143 + 0.4285714286c

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