5(I-4)=-9u-48

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Solution for 5(I-4)=-9u-48 equation: 



5(-4)=-9I-48

We move all terms to the left:

5(-4)-(-9I-48)=0

We add all the numbers together, and all the variables

-(-9I-48)-20=0

We get rid of parentheses

9I+48-20=0

We add all the numbers together, and all the variables

9I+28=0

We move all terms containing I to the left, all other terms to the right

9I=-28

I=-28/9

I=-3+1/9

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