5(I2)=10(3k+9)

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Solution for 5(I2)=10(3k+9) equation: 



5(2)=10(3I+9)

We move all terms to the left:

5(2)-(10(3I+9))=0



We calculate terms in parentheses: -(10(3I+9)), so:

10(3I+9)

We multiply parentheses

30I+90

Back to the equation:

-(30I+90)



We get rid of parentheses

-30I-90+52=0

We add all the numbers together, and all the variables

-30I-38=0

We move all terms containing I to the left, all other terms to the right

-30I=38

I=38/-30

I=-1+4/15

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