5(I2)=10(3k+9)

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Solution for 5(I2)=10(3k+9) equation:



5(2)=10(3I+9)
We move all terms to the left:
5(2)-(10(3I+9))=0
We calculate terms in parentheses: -(10(3I+9)), so:
10(3I+9)
We multiply parentheses
30I+90
Back to the equation:
-(30I+90)
We get rid of parentheses
-30I-90+52=0
We add all the numbers together, and all the variables
-30I-38=0
We move all terms containing I to the left, all other terms to the right
-30I=38
I=38/-30
I=-1+4/15

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