5(X-2)+2X=7(X+4)-38

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Solution for 5(X-2)+2X=7(X+4)-38 equation: 


Simplifying
5(X + -2) + 2X = 7(X + 4) + -38

Reorder the terms:
5(-2 + X) + 2X = 7(X + 4) + -38
(-2 * 5 + X * 5) + 2X = 7(X + 4) + -38
(-10 + 5X) + 2X = 7(X + 4) + -38

Combine like terms: 5X + 2X = 7X
-10 + 7X = 7(X + 4) + -38

Reorder the terms:
-10 + 7X = 7(4 + X) + -38
-10 + 7X = (4 * 7 + X * 7) + -38
-10 + 7X = (28 + 7X) + -38

Reorder the terms:
-10 + 7X = 28 + -38 + 7X

Combine like terms: 28 + -38 = -10
-10 + 7X = -10 + 7X

Add '10' to each side of the equation.
-10 + 10 + 7X = -10 + 10 + 7X

Combine like terms: -10 + 10 = 0
0 + 7X = -10 + 10 + 7X
7X = -10 + 10 + 7X

Combine like terms: -10 + 10 = 0
7X = 0 + 7X
7X = 7X

Add '-7X' to each side of the equation.
7X + -7X = 7X + -7X

Combine like terms: 7X + -7X = 0
0 = 7X + -7X

Combine like terms: 7X + -7X = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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