5(Y-2)=3y+6-2(-3y-1)

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Solution for 5(Y-2)=3y+6-2(-3y-1) equation: 



5(-2)=3Y+6-2(-3Y-1)

We move all terms to the left:

5(-2)-(3Y+6-2(-3Y-1))=0

We add all the numbers together, and all the variables

-(3Y+6-2(-3Y-1))-10=0



We calculate terms in parentheses: -(3Y+6-2(-3Y-1)), so:

3Y+6-2(-3Y-1)

determiningTheFunctionDomain
3Y-2(-3Y-1)+6

We multiply parentheses

3Y+6Y+2+6

We add all the numbers together, and all the variables

9Y+8

Back to the equation:

-(9Y+8)



We get rid of parentheses

-9Y-8-10=0

We add all the numbers together, and all the variables

-9Y-18=0

We move all terms containing Y to the left, all other terms to the right

-9Y=18

Y=18/-9

Y=-2

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