5(a+1)-(4a+3)=14

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Solution for 5(a+1)-(4a+3)=14 equation:


Simplifying
5(a + 1) + -1(4a + 3) = 14

Reorder the terms:
5(1 + a) + -1(4a + 3) = 14
(1 * 5 + a * 5) + -1(4a + 3) = 14
(5 + 5a) + -1(4a + 3) = 14

Reorder the terms:
5 + 5a + -1(3 + 4a) = 14
5 + 5a + (3 * -1 + 4a * -1) = 14
5 + 5a + (-3 + -4a) = 14

Reorder the terms:
5 + -3 + 5a + -4a = 14

Combine like terms: 5 + -3 = 2
2 + 5a + -4a = 14

Combine like terms: 5a + -4a = 1a
2 + 1a = 14

Solving
2 + 1a = 14

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 1a = 14 + -2

Combine like terms: 2 + -2 = 0
0 + 1a = 14 + -2
1a = 14 + -2

Combine like terms: 14 + -2 = 12
1a = 12

Divide each side by '1'.
a = 12

Simplifying
a = 12

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