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5(a+1)=2(5-a)
We move all terms to the left:
5(a+1)-(2(5-a))=0
We add all the numbers together, and all the variables
5(a+1)-(2(-1a+5))=0
We multiply parentheses
5a-(2(-1a+5))+5=0
We calculate terms in parentheses: -(2(-1a+5)), so:We get rid of parentheses
2(-1a+5)
We multiply parentheses
-2a+10
Back to the equation:
-(-2a+10)
5a+2a-10+5=0
We add all the numbers together, and all the variables
7a-5=0
We move all terms containing a to the left, all other terms to the right
7a=5
a=5/7
a=5/7
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