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5(a+1)=2(a-5)
We move all terms to the left:
5(a+1)-(2(a-5))=0
We multiply parentheses
5a-(2(a-5))+5=0
We calculate terms in parentheses: -(2(a-5)), so:We get rid of parentheses
2(a-5)
We multiply parentheses
2a-10
Back to the equation:
-(2a-10)
5a-2a+10+5=0
We add all the numbers together, and all the variables
3a+15=0
We move all terms containing a to the left, all other terms to the right
3a=-15
a=-15/3
a=-5
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