5(a+2)=3(3a-5)=1

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Solution for 5(a+2)=3(3a-5)=1 equation: 



5(a+2)=3(3a-5)=1

We move all terms to the left:

5(a+2)-(3(3a-5))=0

We multiply parentheses

5a-(3(3a-5))+10=0



We calculate terms in parentheses: -(3(3a-5)), so:

3(3a-5)

We multiply parentheses

9a-15

Back to the equation:

-(9a-15)



We get rid of parentheses

5a-9a+15+10=0

We add all the numbers together, and all the variables

-4a+25=0

We move all terms containing a to the left, all other terms to the right

-4a=-25

a=-25/-4

a=6+1/4

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